211312120012333 has 4 divisors (see below), whose sum is σ = 211326848689120. Its totient is φ = 211297391335548.

The previous prime is 211312120012321. The next prime is 211312120012337. The reversal of 211312120012333 is 333210021213112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211312120012333 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211312120012298 and 211312120012307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211312120012337) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7364316873 + ... + 7364345566.

It is an arithmetic number, because the mean of its divisors is an integer number (52831712172280).

Almost surely, 2^{211312120012333} is an apocalyptic number.

It is an amenable number.

211312120012333 is a deficient number, since it is larger than the sum of its proper divisors (14728676787).

211312120012333 is a wasteful number, since it uses less digits than its factorization.

211312120012333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14728676786.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 211312120012333 its reverse (333210021213112), we get a palindrome (544522141225445).

The spelling of 211312120012333 in words is "two hundred eleven trillion, three hundred twelve billion, one hundred twenty million, twelve thousand, three hundred thirty-three".