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21131212231303 = 51059413858717
BaseRepresentation
bin1001100110111111111100…
…11001100001001010000111
32202211010100111211220111021
410303133332121201022013
510232203210312400203
6112535313410052011
74310452065235216
oct463377631411207
982733314756437
1021131212231303
116807773462409
12245345427a007
13ba388463b915
14530a82b6507d
15269a10ab55bd
hex1337fe661287

21131212231303 has 4 divisors (see below), whose sum is σ = 21131626141080. Its totient is φ = 21130798321528.

The previous prime is 21131212231301. The next prime is 21131212231307. The reversal of 21131212231303 is 30313221213112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21131212231303 - 21 = 21131212231301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21131212231301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 206878300 + ... + 206980417.

It is an arithmetic number, because the mean of its divisors is an integer number (5282906535270).

Almost surely, 221131212231303 is an apocalyptic number.

21131212231303 is a deficient number, since it is larger than the sum of its proper divisors (413909777).

21131212231303 is an equidigital number, since it uses as much as digits as its factorization.

21131212231303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 413909776.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 21131212231303 its reverse (30313221213112), we get a palindrome (51444433444415).

The spelling of 21131212231303 in words is "twenty-one trillion, one hundred thirty-one billion, two hundred twelve million, two hundred thirty-one thousand, three hundred three".

Divisors: 1 51059 413858717 21131212231303