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211312122313081 is a prime number
BaseRepresentation
bin110000000010111111101111…
…111111001011100101111001
31000201012020112010111001222111
4300002333233333023211321
5210144114211303004311
62025231240541252321
762336540244424246
oct6002775777134571
91021166463431874
10211312122313081
116136aa71171819
121b8498562640a1
1390ba855b0004a
143a277c02785cd
151966aa7288d21
hexc02feffcb979

211312122313081 has 2 divisors, whose sum is σ = 211312122313082. Its totient is φ = 211312122313080.

The previous prime is 211312122312979. The next prime is 211312122313087. The reversal of 211312122313081 is 180313221213112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107641849253481 + 103670273059600 = 10375059^2 + 10181860^2 .

It is a cyclic number.

It is not a de Polignac number, because 211312122313081 - 27 = 211312122312953 is a prime.

It is a super-2 number, since 2×2113121223130812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (211312122313087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105656061156540 + 105656061156541.

It is an arithmetic number, because the mean of its divisors is an integer number (105656061156541).

Almost surely, 2211312122313081 is an apocalyptic number.

It is an amenable number.

211312122313081 is a deficient number, since it is larger than the sum of its proper divisors (1).

211312122313081 is an equidigital number, since it uses as much as digits as its factorization.

211312122313081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 31.

Adding to 211312122313081 its reverse (180313221213112), we get a palindrome (391625343526193).

The spelling of 211312122313081 in words is "two hundred eleven trillion, three hundred twelve billion, one hundred twenty-two million, three hundred thirteen thousand, eighty-one".