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2113130340131 is a prime number
BaseRepresentation
bin11110110000000000011…
…000100001111100100011
321111000100200112120201112
4132300000120201330203
5234110142331341011
64254431512453535
7305445224346416
oct36600030417443
97430320476645
102113130340131
1174519aa95858
122a16570aa2ab
13124362450035
14743c16c7b7d
1539e79d1358b
hex1ec00621f23

2113130340131 has 2 divisors, whose sum is σ = 2113130340132. Its totient is φ = 2113130340130.

The previous prime is 2113130340077. The next prime is 2113130340151. The reversal of 2113130340131 is 1310430313112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2113130340131 - 214 = 2113130323747 is a prime.

It is a super-2 number, since 2×21131303401312 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 2113130340097 and 2113130340106.

It is not a weakly prime, because it can be changed into another prime (2113130340151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056565170065 + 1056565170066.

It is an arithmetic number, because the mean of its divisors is an integer number (1056565170066).

Almost surely, 22113130340131 is an apocalyptic number.

2113130340131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2113130340131 is an equidigital number, since it uses as much as digits as its factorization.

2113130340131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 2113130340131 its reverse (1310430313112), we get a palindrome (3423560653243).

The spelling of 2113130340131 in words is "two trillion, one hundred thirteen billion, one hundred thirty million, three hundred forty thousand, one hundred thirty-one".