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211313121401 is a prime number
BaseRepresentation
bin1100010011001100111…
…1100101100001111001
3202012102202220210112202
43010303033211201321
511430232124341101
6241024221315545
721160351616144
oct3046317454171
9665382823482
10211313121401
1181687825808
1234b54405bb5
1316c08089b55
14a3287bd05b
15576b76536b
hex31333e5879

211313121401 has 2 divisors, whose sum is σ = 211313121402. Its totient is φ = 211313121400.

The previous prime is 211313121289. The next prime is 211313121407. The reversal of 211313121401 is 104121313112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 209993979001 + 1319142400 = 458251^2 + 36320^2 .

It is a cyclic number.

It is not a de Polignac number, because 211313121401 - 230 = 210239379577 is a prime.

It is not a weakly prime, because it can be changed into another prime (211313121407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105656560700 + 105656560701.

It is an arithmetic number, because the mean of its divisors is an integer number (105656560701).

Almost surely, 2211313121401 is an apocalyptic number.

It is an amenable number.

211313121401 is a deficient number, since it is larger than the sum of its proper divisors (1).

211313121401 is an equidigital number, since it uses as much as digits as its factorization.

211313121401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 211313121401 its reverse (104121313112), we get a palindrome (315434434513).

The spelling of 211313121401 in words is "two hundred eleven billion, three hundred thirteen million, one hundred twenty-one thousand, four hundred one".