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21131314033 is a prime number
BaseRepresentation
bin10011101011100001…
…100100001101110001
32000112200021222100111
4103223201210031301
5321234104022113
613412501221321
71345440130354
oct235341441561
960480258314
1021131314033
118a64091aa5
124118a01841
131cb9ba071b
14104665629b
1583a23a13d
hex4eb864371

21131314033 has 2 divisors, whose sum is σ = 21131314034. Its totient is φ = 21131314032.

The previous prime is 21131313997. The next prime is 21131314091. The reversal of 21131314033 is 33041313112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 18586414224 + 2544899809 = 136332^2 + 50447^2 .

It is a cyclic number.

It is not a de Polignac number, because 21131314033 - 213 = 21131305841 is a prime.

It is a super-2 number, since 2×211313140332 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21131313995 and 21131314013.

It is not a weakly prime, because it can be changed into another prime (21131314133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10565657016 + 10565657017.

It is an arithmetic number, because the mean of its divisors is an integer number (10565657017).

Almost surely, 221131314033 is an apocalyptic number.

It is an amenable number.

21131314033 is a deficient number, since it is larger than the sum of its proper divisors (1).

21131314033 is an equidigital number, since it uses as much as digits as its factorization.

21131314033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 21131314033 its reverse (33041313112), we get a palindrome (54172627145).

The spelling of 21131314033 in words is "twenty-one billion, one hundred thirty-one million, three hundred fourteen thousand, thirty-three".