Base | Representation |
---|---|
bin | 1100010011001101001… |
… | …1000001011110110001 |
3 | 202012102211121120101011 |
4 | 3010303103001132301 |
5 | 11430232342203241 |
6 | 241024252510521 |
7 | 21160362360553 |
oct | 3046323013661 |
9 | 665384546334 |
10 | 211314022321 |
11 | 81688290676 |
12 | 34b5477b441 |
13 | 16c08313c3c |
14 | a3289754d3 |
15 | 576b892281 |
hex | 31334c17b1 |
211314022321 has 2 divisors, whose sum is σ = 211314022322. Its totient is φ = 211314022320.
The previous prime is 211314022279. The next prime is 211314022333. The reversal of 211314022321 is 123220413112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 112852996096 + 98461026225 = 335936^2 + 313785^2 .
It is a cyclic number.
It is not a de Polignac number, because 211314022321 - 227 = 211179804593 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 211314022292 and 211314022301.
It is not a weakly prime, because it can be changed into another prime (211314022351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105657011160 + 105657011161.
It is an arithmetic number, because the mean of its divisors is an integer number (105657011161).
Almost surely, 2211314022321 is an apocalyptic number.
It is an amenable number.
211314022321 is a deficient number, since it is larger than the sum of its proper divisors (1).
211314022321 is an equidigital number, since it uses as much as digits as its factorization.
211314022321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 211314022321 its reverse (123220413112), we get a palindrome (334534435433).
The spelling of 211314022321 in words is "two hundred eleven billion, three hundred fourteen million, twenty-two thousand, three hundred twenty-one".
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