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2113141081 is a prime number
BaseRepresentation
bin111110111110011…
…1111100101011001
312110021020200121111
41331330333211121
513311431003311
6545403540321
7103236255112
oct17574774531
95407220544
102113141081
119948a4197
124ab82a6a1
13278a3c34c
1416090b209
15c57b0d21
hex7df3f959

2113141081 has 2 divisors, whose sum is σ = 2113141082. Its totient is φ = 2113141080.

The previous prime is 2113141049. The next prime is 2113141159. The reversal of 2113141081 is 1801413112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2108279056 + 4862025 = 45916^2 + 2205^2 .

It is a cyclic number.

It is not a de Polignac number, because 2113141081 - 25 = 2113141049 is a prime.

It is a super-2 number, since 2×21131410812 = 8930730456419697122, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2113145081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056570540 + 1056570541.

It is an arithmetic number, because the mean of its divisors is an integer number (1056570541).

Almost surely, 22113141081 is an apocalyptic number.

It is an amenable number.

2113141081 is a deficient number, since it is larger than the sum of its proper divisors (1).

2113141081 is an equidigital number, since it uses as much as digits as its factorization.

2113141081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 22.

The square root of 2113141081 is about 45968.9142899851. The cubic root of 2113141081 is about 1283.2447545691.

Adding to 2113141081 its reverse (1801413112), we get a palindrome (3914554193).

The spelling of 2113141081 in words is "two billion, one hundred thirteen million, one hundred forty-one thousand, eighty-one".