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21131431231241 is a prime number
BaseRepresentation
bin1001100111000000010110…
…11100111011111100001001
32202211010220202221020221002
410303200023130323330021
510232204132343344431
6112535351232024345
74310460364555052
oct463401334737411
982733822836832
1021131431231241
1168078760422a1
1224534b56920b5
13ba38bab19096
14530aa3c91729
15269a24e243cb
hex13380b73bf09

21131431231241 has 2 divisors, whose sum is σ = 21131431231242. Its totient is φ = 21131431231240.

The previous prime is 21131431231201. The next prime is 21131431231279. The reversal of 21131431231241 is 14213213413112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10813870518025 + 10317560713216 = 3288445^2 + 3212096^2 .

It is a cyclic number.

It is not a de Polignac number, because 21131431231241 - 218 = 21131430969097 is a prime.

It is not a weakly prime, because it can be changed into another prime (21131431231201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10565715615620 + 10565715615621.

It is an arithmetic number, because the mean of its divisors is an integer number (10565715615621).

Almost surely, 221131431231241 is an apocalyptic number.

It is an amenable number.

21131431231241 is a deficient number, since it is larger than the sum of its proper divisors (1).

21131431231241 is an equidigital number, since it uses as much as digits as its factorization.

21131431231241 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3456, while the sum is 29.

Adding to 21131431231241 its reverse (14213213413112), we get a palindrome (35344644644353).

The spelling of 21131431231241 in words is "twenty-one trillion, one hundred thirty-one billion, four hundred thirty-one million, two hundred thirty-one thousand, two hundred forty-one".