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211320001001 is a prime number
BaseRepresentation
bin1100010011001110100…
…1110101000111101001
3202012110020212022120202
43010303221311013221
511430240410013001
6241025025001545
721160464241244
oct3046351650751
9665406768522
10211320001001
11816906a452a
1234b567832b5
1316c09628315
14a32969025b
15576c17396b
hex3133a751e9

211320001001 has 2 divisors, whose sum is σ = 211320001002. Its totient is φ = 211320001000.

The previous prime is 211320000989. The next prime is 211320001021. The reversal of 211320001001 is 100100023112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 177598187776 + 33721813225 = 421424^2 + 183635^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211320001001 is a prime.

It is a super-2 number, since 2×2113200010012 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (211320001021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105660000500 + 105660000501.

It is an arithmetic number, because the mean of its divisors is an integer number (105660000501).

Almost surely, 2211320001001 is an apocalyptic number.

It is an amenable number.

211320001001 is a deficient number, since it is larger than the sum of its proper divisors (1).

211320001001 is an equidigital number, since it uses as much as digits as its factorization.

211320001001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 211320001001 its reverse (100100023112), we get a palindrome (311420024113).

The spelling of 211320001001 in words is "two hundred eleven billion, three hundred twenty million, one thousand, one".