Base | Representation |
---|---|
bin | 11110110000000100100… |
… | …110100010111010111001 |
3 | 21111000112121201201120022 |
4 | 132300010212202322321 |
5 | 234110313441414001 |
6 | 4254442521540225 |
7 | 305450044113443 |
oct | 36600446427271 |
9 | 7430477651508 |
10 | 2113201123001 |
11 | 745226a40aa1 |
12 | 2a1676944675 |
13 | 124374003ca7 |
14 | 743cac71493 |
15 | 39e8114611b |
hex | 1ec049a2eb9 |
2113201123001 has 2 divisors, whose sum is σ = 2113201123002. Its totient is φ = 2113201123000.
The previous prime is 2113201122973. The next prime is 2113201123039. The reversal of 2113201123001 is 1003211023112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1372878546601 + 740322576400 = 1171699^2 + 860420^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2113201123001 is a prime.
It is not a weakly prime, because it can be changed into another prime (2113201123051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056600561500 + 1056600561501.
It is an arithmetic number, because the mean of its divisors is an integer number (1056600561501).
Almost surely, 22113201123001 is an apocalyptic number.
It is an amenable number.
2113201123001 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113201123001 is an equidigital number, since it uses as much as digits as its factorization.
2113201123001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 2113201123001 its reverse (1003211023112), we get a palindrome (3116412146113).
The spelling of 2113201123001 in words is "two trillion, one hundred thirteen billion, two hundred one million, one hundred twenty-three thousand, one".
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