Base | Representation |
---|---|
bin | 1100010011001110110… |
… | …1101011100011100001 |
3 | 202012110022202121012221 |
4 | 3010303231223203201 |
5 | 11430241134313101 |
6 | 241025102351041 |
7 | 21160505644144 |
oct | 3046355534341 |
9 | 665408677187 |
10 | 211321010401 |
11 | 81691223946 |
12 | 34b56b8b481 |
13 | 16c098bc8b7 |
14 | a32987405b |
15 | 576c2c2aa1 |
hex | 3133b6b8e1 |
211321010401 has 2 divisors, whose sum is σ = 211321010402. Its totient is φ = 211321010400.
The previous prime is 211321010387. The next prime is 211321010413. The reversal of 211321010401 is 104010123112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 187164390625 + 24156619776 = 432625^2 + 155424^2 .
It is a cyclic number.
It is not a de Polignac number, because 211321010401 - 215 = 211320977633 is a prime.
It is not a weakly prime, because it can be changed into another prime (211321010491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105660505200 + 105660505201.
It is an arithmetic number, because the mean of its divisors is an integer number (105660505201).
Almost surely, 2211321010401 is an apocalyptic number.
It is an amenable number.
211321010401 is a deficient number, since it is larger than the sum of its proper divisors (1).
211321010401 is an equidigital number, since it uses as much as digits as its factorization.
211321010401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 211321010401 its reverse (104010123112), we get a palindrome (315331133513).
The spelling of 211321010401 in words is "two hundred eleven billion, three hundred twenty-one million, ten thousand, four hundred one".
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