Base | Representation |
---|---|
bin | 1100010011001110111… |
… | …0000110100101101011 |
3 | 202012110022222020010001 |
4 | 3010303232012211223 |
5 | 11430241201334011 |
6 | 241025105003431 |
7 | 21160506615031 |
oct | 3046356064553 |
9 | 665408866101 |
10 | 211321121131 |
11 | 8169129a05a |
12 | 34b57023577 |
13 | 16c0992b113 |
14 | a3298a2551 |
15 | 576c2e57c1 |
hex | 3133b8696b |
211321121131 has 2 divisors, whose sum is σ = 211321121132. Its totient is φ = 211321121130.
The previous prime is 211321121107. The next prime is 211321121227. The reversal of 211321121131 is 131121123112.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211321121131 is a prime.
It is a super-2 number, since 2×2113211211312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 211321121099 and 211321121108.
It is not a weakly prime, because it can be changed into another prime (211321121101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105660560565 + 105660560566.
It is an arithmetic number, because the mean of its divisors is an integer number (105660560566).
Almost surely, 2211321121131 is an apocalyptic number.
211321121131 is a deficient number, since it is larger than the sum of its proper divisors (1).
211321121131 is an equidigital number, since it uses as much as digits as its factorization.
211321121131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 72, while the sum is 19.
Adding to 211321121131 its reverse (131121123112), we get a palindrome (342442244243).
The spelling of 211321121131 in words is "two hundred eleven billion, three hundred twenty-one million, one hundred twenty-one thousand, one hundred thirty-one".
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