2113214003 has 2 divisors, whose sum is σ = 2113214004. Its totient is φ = 2113214002.

The previous prime is 2113213981. The next prime is 2113214009. The reversal of 2113214003 is 3004123112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2113214003 - 2¹² = 2113209907 is a prime.

It is a super-4 number, since 4×2113214003⁴ (a number of 38 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (2113214009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056607001 + 1056607002.

It is an arithmetic number, because the mean of its divisors is an integer number (1056607002).

Almost surely, 2^2113214003 is an apocalyptic number.

2113214003 is a deficient number, since it is larger than the sum of its proper divisors (1).

2113214003 is an equidigital number, since it uses as much as digits as its factorization.

2113214003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 2113214003 is about 45969.7074495803. The cubic root of 2113214003 is about 1283.2595154857.

Adding to 2113214003 its reverse (3004123112), we get a palindrome (5117337115).

The spelling of 2113214003 in words is "two billion, one hundred thirteen million, two hundred fourteen thousand, three".