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2113220011241 is a prime number
BaseRepresentation
bin11110110000000101101…
…110100110010011101001
321111000120221021100100202
4132300011232212103221
5234110333310324431
64254444434441545
7305450363502263
oct36600556462351
97430527240322
102113220011241
11745236672009
122a16811332b5
13124377bb8371
14743cd58ab33
1539e82b278cb
hex1ec05ba64e9

2113220011241 has 2 divisors, whose sum is σ = 2113220011242. Its totient is φ = 2113220011240.

The previous prime is 2113220011151. The next prime is 2113220011297. The reversal of 2113220011241 is 1421100223112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1334034240016 + 779185771225 = 1155004^2 + 882715^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2113220011241 is a prime.

It is not a weakly prime, because it can be changed into another prime (2113220011841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056610005620 + 1056610005621.

It is an arithmetic number, because the mean of its divisors is an integer number (1056610005621).

Almost surely, 22113220011241 is an apocalyptic number.

It is an amenable number.

2113220011241 is a deficient number, since it is larger than the sum of its proper divisors (1).

2113220011241 is an equidigital number, since it uses as much as digits as its factorization.

2113220011241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 2113220011241 its reverse (1421100223112), we get a palindrome (3534320234353).

The spelling of 2113220011241 in words is "two trillion, one hundred thirteen billion, two hundred twenty million, eleven thousand, two hundred forty-one".