Base | Representation |
---|---|
bin | 11110110000000101101… |
… | …111110010101101010001 |
3 | 21111000120221212020121222 |
4 | 132300011233302231101 |
5 | 234110333400333202 |
6 | 4254444445254425 |
7 | 305450366244524 |
oct | 36600557625521 |
9 | 7430527766558 |
10 | 2113220324177 |
11 | 745236866136 |
12 | 2a1681264415 |
13 | 124377c97931 |
14 | 743cd62cbbb |
15 | 39e82b8a4a2 |
hex | 1ec05bf2b51 |
2113220324177 has 2 divisors, whose sum is σ = 2113220324178. Its totient is φ = 2113220324176.
The previous prime is 2113220323997. The next prime is 2113220324209. The reversal of 2113220324177 is 7714230223112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2075800903696 + 37419420481 = 1440764^2 + 193441^2 .
It is a cyclic number.
It is not a de Polignac number, because 2113220324177 - 216 = 2113220258641 is a prime.
It is not a weakly prime, because it can be changed into another prime (2113270324177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056610162088 + 1056610162089.
It is an arithmetic number, because the mean of its divisors is an integer number (1056610162089).
Almost surely, 22113220324177 is an apocalyptic number.
It is an amenable number.
2113220324177 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113220324177 is an equidigital number, since it uses as much as digits as its factorization.
2113220324177 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28224, while the sum is 35.
Adding to 2113220324177 its reverse (7714230223112), we get a palindrome (9827450547289).
The spelling of 2113220324177 in words is "two trillion, one hundred thirteen billion, two hundred twenty million, three hundred twenty-four thousand, one hundred seventy-seven".
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