Base | Representation |
---|---|
bin | 1100010011010001011… |
… | …1100111000111000011 |
3 | 202012111002110001012012 |
4 | 3010310113213013003 |
5 | 11430301443032433 |
6 | 241030134123135 |
7 | 21161001244265 |
oct | 3046427470703 |
9 | 665432401165 |
10 | 211332002243 |
11 | 8169745120a |
12 | 34b5a7b04ab |
13 | 16c0bc6aa4b |
14 | a32b0d5b35 |
15 | 576d244848 |
hex | 31345e71c3 |
211332002243 has 2 divisors, whose sum is σ = 211332002244. Its totient is φ = 211332002242.
The previous prime is 211332002201. The next prime is 211332002249. The reversal of 211332002243 is 342200233112.
211332002243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211332002243 - 210 = 211332001219 is a prime.
It is a super-2 number, since 2×2113320022432 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211332002249) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105666001121 + 105666001122.
It is an arithmetic number, because the mean of its divisors is an integer number (105666001122).
Almost surely, 2211332002243 is an apocalyptic number.
211332002243 is a deficient number, since it is larger than the sum of its proper divisors (1).
211332002243 is an equidigital number, since it uses as much as digits as its factorization.
211332002243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 211332002243 its reverse (342200233112), we get a palindrome (553532235355).
The spelling of 211332002243 in words is "two hundred eleven billion, three hundred thirty-two million, two thousand, two hundred forty-three".
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