Base | Representation |
---|---|
bin | 110000000011010010010111… |
… | …100001101110000000111111 |
3 | 1000201021011010022112202221000 |
4 | 300003102113201232000333 |
5 | 210144431131413444411 |
6 | 2025244344335541343 |
7 | 62341145524632333 |
oct | 6003222741560077 |
9 | 1021234108482830 |
10 | 211332113031231 |
11 | 6137849a431195 |
12 | 1b8516b508a853 |
13 | 90bc6c05a7c5a |
14 | 3a287592257c3 |
15 | 19673772be956 |
hex | c0349786e03f |
211332113031231 has 32 divisors (see below), whose sum is σ = 331524628920000. Its totient is φ = 132591231452160.
The previous prime is 211332113031227. The next prime is 211332113031287. The reversal of 211332113031231 is 132130311233112.
211332113031231 is a `hidden beast` number, since 2 + 1 + 1 + 3 + 321 + 1 + 303 + 1 + 2 + 31 = 666.
It is not a de Polignac number, because 211332113031231 - 22 = 211332113031227 is a prime.
It is a super-2 number, since 2×2113321130312312 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 211332113031195 and 211332113031204.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211332113030231) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9615880 + ... + 22696461.
It is an arithmetic number, because the mean of its divisors is an integer number (10360144653750).
Almost surely, 2211332113031231 is an apocalyptic number.
211332113031231 is a deficient number, since it is larger than the sum of its proper divisors (120192515888769).
211332113031231 is a wasteful number, since it uses less digits than its factorization.
211332113031231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32326616 (or 32326610 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 27.
Adding to 211332113031231 its reverse (132130311233112), we get a palindrome (343462424264343).
The spelling of 211332113031231 in words is "two hundred eleven trillion, three hundred thirty-two billion, one hundred thirteen million, thirty-one thousand, two hundred thirty-one".
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