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2113330401251 is a prime number
BaseRepresentation
bin11110110000001100010…
…011101100111111100011
321111000212121222201222122
4132300030103230333203
5234111100040320001
64254503420454455
7305453204010116
oct36601423547743
97430777881878
102113330401251
11745292a0a723
122a16b20aa42b
13124394a290b4
14744000c457d
1539e8c680b1b
hex1ec0c4ecfe3

2113330401251 has 2 divisors, whose sum is σ = 2113330401252. Its totient is φ = 2113330401250.

The previous prime is 2113330401071. The next prime is 2113330401263. The reversal of 2113330401251 is 1521040333112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2113330401251 - 210 = 2113330400227 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2113330401251.

It is not a weakly prime, because it can be changed into another prime (2113330401271) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056665200625 + 1056665200626.

It is an arithmetic number, because the mean of its divisors is an integer number (1056665200626).

Almost surely, 22113330401251 is an apocalyptic number.

2113330401251 is a deficient number, since it is larger than the sum of its proper divisors (1).

2113330401251 is an equidigital number, since it uses as much as digits as its factorization.

2113330401251 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 2113330401251 its reverse (1521040333112), we get a palindrome (3634370734363).

The spelling of 2113330401251 in words is "two trillion, one hundred thirteen billion, three hundred thirty million, four hundred one thousand, two hundred fifty-one".