Base | Representation |
---|---|
bin | 11110110000001100010… |
… | …011101100111111100011 |
3 | 21111000212121222201222122 |
4 | 132300030103230333203 |
5 | 234111100040320001 |
6 | 4254503420454455 |
7 | 305453204010116 |
oct | 36601423547743 |
9 | 7430777881878 |
10 | 2113330401251 |
11 | 745292a0a723 |
12 | 2a16b20aa42b |
13 | 124394a290b4 |
14 | 744000c457d |
15 | 39e8c680b1b |
hex | 1ec0c4ecfe3 |
2113330401251 has 2 divisors, whose sum is σ = 2113330401252. Its totient is φ = 2113330401250.
The previous prime is 2113330401071. The next prime is 2113330401263. The reversal of 2113330401251 is 1521040333112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2113330401251 - 210 = 2113330400227 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2113330401251.
It is not a weakly prime, because it can be changed into another prime (2113330401271) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056665200625 + 1056665200626.
It is an arithmetic number, because the mean of its divisors is an integer number (1056665200626).
Almost surely, 22113330401251 is an apocalyptic number.
2113330401251 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113330401251 is an equidigital number, since it uses as much as digits as its factorization.
2113330401251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 2113330401251 its reverse (1521040333112), we get a palindrome (3634370734363).
The spelling of 2113330401251 in words is "two trillion, one hundred thirteen billion, three hundred thirty million, four hundred one thousand, two hundred fifty-one".
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