Base | Representation |
---|---|
bin | 1100010011010001110… |
… | …0010011010111010011 |
3 | 202012111011202112012211 |
4 | 3010310130103113103 |
5 | 11430302301411313 |
6 | 241030220332551 |
7 | 21161014555651 |
oct | 3046434232723 |
9 | 665434675184 |
10 | 211333232083 |
11 | 81698111206 |
12 | 34b5b0a4157 |
13 | 16c0c2ab76c |
14 | a32b335dd1 |
15 | 576d3d8e3d |
hex | 31347135d3 |
211333232083 has 2 divisors, whose sum is σ = 211333232084. Its totient is φ = 211333232082.
The previous prime is 211333232057. The next prime is 211333232113. The reversal of 211333232083 is 380232333112.
211333232083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211333232083 - 237 = 73894278611 is a prime.
It is not a weakly prime, because it can be changed into another prime (211333242083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105666616041 + 105666616042.
It is an arithmetic number, because the mean of its divisors is an integer number (105666616042).
Almost surely, 2211333232083 is an apocalyptic number.
211333232083 is a deficient number, since it is larger than the sum of its proper divisors (1).
211333232083 is an equidigital number, since it uses as much as digits as its factorization.
211333232083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 211333232083 its reverse (380232333112), we get a palindrome (591565565195).
The spelling of 211333232083 in words is "two hundred eleven billion, three hundred thirty-three million, two hundred thirty-two thousand, eighty-three".
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