Base | Representation |
---|---|
bin | 11110110000001101000… |
… | …111101101010100110111 |
3 | 21111000220120122100202002 |
4 | 132300031013231110313 |
5 | 234111112033042403 |
6 | 4254505025005515 |
7 | 305453430620051 |
oct | 36601507552467 |
9 | 7430816570662 |
10 | 2113344034103 |
11 | 74529a681245 |
12 | 2a16b678389b |
13 | 1243977c0383 |
14 | 74401c328d1 |
15 | 39e8d975188 |
hex | 1ec0d1ed537 |
2113344034103 has 4 divisors (see below), whose sum is σ = 2113364220720. Its totient is φ = 2113323847488.
The previous prime is 2113344034069. The next prime is 2113344034181. The reversal of 2113344034103 is 3014304433112.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2113344034103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2113344036103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9935450 + ... + 10145927.
It is an arithmetic number, because the mean of its divisors is an integer number (528341055180).
Almost surely, 22113344034103 is an apocalyptic number.
2113344034103 is a deficient number, since it is larger than the sum of its proper divisors (20186617).
2113344034103 is a wasteful number, since it uses less digits than its factorization.
2113344034103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20186616.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 2113344034103 its reverse (3014304433112), we get a palindrome (5127648467215).
The spelling of 2113344034103 in words is "two trillion, one hundred thirteen billion, three hundred forty-four million, thirty-four thousand, one hundred three".
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