Base | Representation |
---|---|
bin | 11110110000010000100… |
… | …010010010011000110111 |
3 | 21111001001120110110110200 |
4 | 132300100202102120313 |
5 | 234111221220131203 |
6 | 4254514433051543 |
7 | 305455024635111 |
oct | 36602042223067 |
9 | 7431046413420 |
10 | 2113401333303 |
11 | 745319a57a57 |
12 | 2a17119b6bb3 |
13 | 1243a6632c20 |
14 | 744096aa3b1 |
15 | 39e939e29a3 |
hex | 1ec10892637 |
2113401333303 has 48 divisors (see below), whose sum is σ = 3368078794080. Its totient is φ = 1268689766400.
The previous prime is 2113401333289. The next prime is 2113401333319. The reversal of 2113401333303 is 3033331043112.
2113401333303 is a `hidden beast` number, since 2 + 1 + 1 + 340 + 13 + 3 + 3 + 303 = 666.
It is not a de Polignac number, because 2113401333303 - 210 = 2113401332279 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2113401333343) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 54719263 + ... + 54757871.
It is an arithmetic number, because the mean of its divisors is an integer number (70168308210).
Almost surely, 22113401333303 is an apocalyptic number.
2113401333303 is a deficient number, since it is larger than the sum of its proper divisors (1254677460777).
2113401333303 is a wasteful number, since it uses less digits than its factorization.
2113401333303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50080 (or 50077 counting only the distinct ones).
The product of its (nonzero) digits is 5832, while the sum is 27.
Adding to 2113401333303 its reverse (3033331043112), we get a palindrome (5146732376415).
The spelling of 2113401333303 in words is "two trillion, one hundred thirteen billion, four hundred one million, three hundred thirty-three thousand, three hundred three".
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