Base | Representation |
---|---|
bin | 11110110000010001001… |
… | …100010001101011010001 |
3 | 21111001002100011200102011 |
4 | 132300101030101223101 |
5 | 234111232024343213 |
6 | 4254515505022521 |
7 | 305455220330632 |
oct | 36602114215321 |
9 | 7431070150364 |
10 | 2113412340433 |
11 | 745325195859 |
12 | 2a1715624a41 |
13 | 1243a89b8014 |
14 | 7440ad33889 |
15 | 39e9496903d |
hex | 1ec11311ad1 |
2113412340433 has 2 divisors, whose sum is σ = 2113412340434. Its totient is φ = 2113412340432.
The previous prime is 2113412340397. The next prime is 2113412340509. The reversal of 2113412340433 is 3340432143112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1789369054929 + 324043285504 = 1337673^2 + 569248^2 .
It is a cyclic number.
It is not a de Polignac number, because 2113412340433 - 217 = 2113412209361 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2113412340395 and 2113412340404.
It is not a weakly prime, because it can be changed into another prime (2113412343433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056706170216 + 1056706170217.
It is an arithmetic number, because the mean of its divisors is an integer number (1056706170217).
Almost surely, 22113412340433 is an apocalyptic number.
It is an amenable number.
2113412340433 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113412340433 is an equidigital number, since it uses as much as digits as its factorization.
2113412340433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 2113412340433 its reverse (3340432143112), we get a palindrome (5453844483545).
The spelling of 2113412340433 in words is "two trillion, one hundred thirteen billion, four hundred twelve million, three hundred forty thousand, four hundred thirty-three".
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