Base | Representation |
---|---|
bin | 110000000011011010110111… |
… | …100011110111100010010101 |
3 | 1000201022000200102022011001221 |
4 | 300003122313203313202111 |
5 | 210200103330020300041 |
6 | 2025252454151050341 |
7 | 62341620645165064 |
oct | 6003326743674225 |
9 | 1021260612264057 |
10 | 211341240400021 |
11 | 61381353607486 |
12 | 1b8534219709b1 |
13 | 90c05165621a4 |
14 | 3a28d835141db |
15 | 196770d75a2d1 |
hex | c036b78f7895 |
211341240400021 has 16 divisors (see below), whose sum is σ = 216796687213248. Its totient is φ = 205951540435200.
The previous prime is 211341240400009. The next prime is 211341240400061. The reversal of 211341240400021 is 120004042143112.
It is a cyclic number.
It is not a de Polignac number, because 211341240400021 - 225 = 211341206845589 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211341240400001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10260610 + ... + 22977436.
It is an arithmetic number, because the mean of its divisors is an integer number (13549792950828).
Almost surely, 2211341240400021 is an apocalyptic number.
It is an amenable number.
211341240400021 is a deficient number, since it is larger than the sum of its proper divisors (5455446813227).
211341240400021 is a wasteful number, since it uses less digits than its factorization.
211341240400021 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12719412.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 211341240400021 its reverse (120004042143112), we get a palindrome (331345282543133).
The spelling of 211341240400021 in words is "two hundred eleven trillion, three hundred forty-one billion, two hundred forty million, four hundred thousand, twenty-one".
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