Base | Representation |
---|---|
bin | 110000000011100111111110… |
… | …011111110101001100000011 |
3 | 1000201100101000022221120000022 |
4 | 300003213332133311030003 |
5 | 210200321141222113201 |
6 | 2025303142543444055 |
7 | 62342626514012306 |
oct | 6003477637651403 |
9 | 1021311008846008 |
10 | 211355315426051 |
11 | 613873165998a5 |
12 | 1b8560ab5b662b |
13 | 90c194a57c464 |
14 | 3a2991a95ab3d |
15 | 1967c8425d41b |
hex | c039fe7f5303 |
211355315426051 has 2 divisors, whose sum is σ = 211355315426052. Its totient is φ = 211355315426050.
The previous prime is 211355315426041. The next prime is 211355315426069. The reversal of 211355315426051 is 150624513553112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211355315426051 - 26 = 211355315425987 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 211355315425993 and 211355315426011.
It is not a weakly prime, because it can be changed into another prime (211355315426041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105677657713025 + 105677657713026.
It is an arithmetic number, because the mean of its divisors is an integer number (105677657713026).
Almost surely, 2211355315426051 is an apocalyptic number.
211355315426051 is a deficient number, since it is larger than the sum of its proper divisors (1).
211355315426051 is an equidigital number, since it uses as much as digits as its factorization.
211355315426051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540000, while the sum is 44.
Adding to 211355315426051 its reverse (150624513553112), we get a palindrome (361979828979163).
The spelling of 211355315426051 in words is "two hundred eleven trillion, three hundred fifty-five billion, three hundred fifteen million, four hundred twenty-six thousand, fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •