2114011313 has 2 divisors, whose sum is σ = 2114011314. Its totient is φ = 2114011312.

The previous prime is 2114011283. The next prime is 2114011331. The reversal of 2114011313 is 3131104112.

Together with next prime (2114011331) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2107544464 + 6466849 = 45908^2 + 2543^2 .

It is a cyclic number.

It is not a de Polignac number, because 2114011313 - 2²² = 2109817009 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2114011291 and 2114011300.

It is not a weakly prime, because it can be changed into another prime (2114011363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057005656 + 1057005657.

It is an arithmetic number, because the mean of its divisors is an integer number (1057005657).

Almost surely, 2^2114011313 is an apocalyptic number.

It is an amenable number.

2114011313 is a deficient number, since it is larger than the sum of its proper divisors (1).

2114011313 is an equidigital number, since it uses as much as digits as its factorization.

2114011313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 2114011313 is about 45978.3787556717. The cubic root of 2114011313 is about 1283.4208853220.

Adding to 2114011313 its reverse (3131104112), we get a palindrome (5245115425).

The spelling of 2114011313 in words is "two billion, one hundred fourteen million, eleven thousand, three hundred thirteen".