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2114011993 is a prime number
BaseRepresentation
bin111111000000001…
…0100001101011001
312110022212221021111
41332000110031121
513312141340433
6545434340321
7103246543162
oct17600241531
95408787244
102114011993
11995339555
124abb8a6a1
13278c85892
14160a96769
15c58d3dcd
hex7e014359

2114011993 has 2 divisors, whose sum is σ = 2114011994. Its totient is φ = 2114011992.

The previous prime is 2114011987. The next prime is 2114011997. The reversal of 2114011993 is 3991104112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1835522649 + 278489344 = 42843^2 + 16688^2 .

It is a cyclic number.

It is not a de Polignac number, because 2114011993 - 25 = 2114011961 is a prime.

It is not a weakly prime, because it can be changed into another prime (2114011997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057005996 + 1057005997.

It is an arithmetic number, because the mean of its divisors is an integer number (1057005997).

Almost surely, 22114011993 is an apocalyptic number.

It is an amenable number.

2114011993 is a deficient number, since it is larger than the sum of its proper divisors (1).

2114011993 is an equidigital number, since it uses as much as digits as its factorization.

2114011993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 31.

The square root of 2114011993 is about 45978.3861504512. The cubic root of 2114011993 is about 1283.4210229318.

It can be divided in two parts, 21140 and 11993, that added together give a palindrome (33133).

The spelling of 2114011993 in words is "two billion, one hundred fourteen million, eleven thousand, nine hundred ninety-three".