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2114013551650 = 25271113283149251
BaseRepresentation
bin11110110000110101000…
…001101101110000100010
321111002122020110101011021
4132300311001231300202
5234113444432123100
64255055303040054
7305506140463210
oct36606501556042
97432566411137
102114013551650
117456035a0730
122a1862a4002a
13124473418cc0
1474466b13cb0
1539ecc625a1a
hex1ec3506dc22

2114013551650 has 192 divisors, whose sum is σ = 5298106899456. Its totient is φ = 606074400000.

The previous prime is 2114013551581. The next prime is 2114013551659. The reversal of 2114013551650 is 561553104112.

It is not an unprimeable number, because it can be changed into a prime (2114013551659) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 14089525 + ... + 14238775.

It is an arithmetic number, because the mean of its divisors is an integer number (27594306768).

Almost surely, 22114013551650 is an apocalyptic number.

2114013551650 is an abundant number, since it is smaller than the sum of its proper divisors (3184093347806).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2114013551650 is a wasteful number, since it uses less digits than its factorization.

2114013551650 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 149577 (or 149572 counting only the distinct ones).

The product of its (nonzero) digits is 18000, while the sum is 34.

Adding to 2114013551650 its reverse (561553104112), we get a palindrome (2675566655762).

The spelling of 2114013551650 in words is "two trillion, one hundred fourteen billion, thirteen million, five hundred fifty-one thousand, six hundred fifty".