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211404012481 is a prime number
BaseRepresentation
bin1100010011100010101…
…0010011101111000001
3202012200002221112200001
43010320222103233001
511430423411344411
6241041225400001
721162534312544
oct3047052235701
9665602845601
10211404012481
1181724065602
1234b7a939001
1316c20b6155c
14a3368bc85b
15577471adc1
hex3138a93bc1

211404012481 has 2 divisors, whose sum is σ = 211404012482. Its totient is φ = 211404012480.

The previous prime is 211404012349. The next prime is 211404012541. The reversal of 211404012481 is 184210404112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 179856569025 + 31547443456 = 424095^2 + 177616^2 .

It is a cyclic number.

It is not a de Polignac number, because 211404012481 - 225 = 211370458049 is a prime.

It is a super-2 number, since 2×2114040124812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (211404018481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105702006240 + 105702006241.

It is an arithmetic number, because the mean of its divisors is an integer number (105702006241).

Almost surely, 2211404012481 is an apocalyptic number.

It is an amenable number.

211404012481 is a deficient number, since it is larger than the sum of its proper divisors (1).

211404012481 is an equidigital number, since it uses as much as digits as its factorization.

211404012481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2048, while the sum is 28.

Adding to 211404012481 its reverse (184210404112), we get a palindrome (395614416593).

The spelling of 211404012481 in words is "two hundred eleven billion, four hundred four million, twelve thousand, four hundred eighty-one".