Base | Representation |
---|---|
bin | 1100010011100010101… |
… | …0010011101111000001 |
3 | 202012200002221112200001 |
4 | 3010320222103233001 |
5 | 11430423411344411 |
6 | 241041225400001 |
7 | 21162534312544 |
oct | 3047052235701 |
9 | 665602845601 |
10 | 211404012481 |
11 | 81724065602 |
12 | 34b7a939001 |
13 | 16c20b6155c |
14 | a3368bc85b |
15 | 577471adc1 |
hex | 3138a93bc1 |
211404012481 has 2 divisors, whose sum is σ = 211404012482. Its totient is φ = 211404012480.
The previous prime is 211404012349. The next prime is 211404012541. The reversal of 211404012481 is 184210404112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 179856569025 + 31547443456 = 424095^2 + 177616^2 .
It is a cyclic number.
It is not a de Polignac number, because 211404012481 - 225 = 211370458049 is a prime.
It is a super-2 number, since 2×2114040124812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211404018481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105702006240 + 105702006241.
It is an arithmetic number, because the mean of its divisors is an integer number (105702006241).
Almost surely, 2211404012481 is an apocalyptic number.
It is an amenable number.
211404012481 is a deficient number, since it is larger than the sum of its proper divisors (1).
211404012481 is an equidigital number, since it uses as much as digits as its factorization.
211404012481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2048, while the sum is 28.
Adding to 211404012481 its reverse (184210404112), we get a palindrome (395614416593).
The spelling of 211404012481 in words is "two hundred eleven billion, four hundred four million, twelve thousand, four hundred eighty-one".
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