2114112113 has 2 divisors, whose sum is σ = 2114112114. Its totient is φ = 2114112112.

The previous prime is 2114112109. The next prime is 2114112149. The reversal of 2114112113 is 3112114112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1368112144 + 745999969 = 36988^2 + 27313^2 .

It is a cyclic number.

It is not a de Polignac number, because 2114112113 - 2² = 2114112109 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2114112091 and 2114112100.

It is not a weakly prime, because it can be changed into another prime (2114112713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057056056 + 1057056057.

It is an arithmetic number, because the mean of its divisors is an integer number (1057056057).

Almost surely, 2^2114112113 is an apocalyptic number.

It is an amenable number.

2114112113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2114112113 is an equidigital number, since it uses as much as digits as its factorization.

2114112113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 48, while the sum is 17.

The square root of 2114112113 is about 45979.4749100074. The cubic root of 2114112113 is about 1283.4412836312.

Adding to 2114112113 its reverse (3112114112), we get a palindrome (5226226225).

The spelling of 2114112113 in words is "two billion, one hundred fourteen million, one hundred twelve thousand, one hundred thirteen".