Base | Representation |
---|---|
bin | 11110110001000010100… |
… | …101110010000110000011 |
3 | 21111010020002122120002020 |
4 | 132301002211302012003 |
5 | 234114431211013103 |
6 | 4255134032252523 |
7 | 305514602630622 |
oct | 36610245620603 |
9 | 7433202576066 |
10 | 2114241110403 |
11 | 74570aa96a14 |
12 | 2a19070a1143 |
13 | 1244ab602056 |
14 | 7448902b6b9 |
15 | 39ee25c5753 |
hex | 1ec42972183 |
2114241110403 has 8 divisors (see below), whose sum is σ = 2827994500368. Its totient is φ = 1404990897024.
The previous prime is 2114241110393. The next prime is 2114241110407. The reversal of 2114241110403 is 3040111424112.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2114241110403 - 233 = 2105651175811 is a prime.
It is a super-2 number, since 2×21142411104032 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2114241110407) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1125793050 + ... + 1125794927.
It is an arithmetic number, because the mean of its divisors is an integer number (353499312546).
Almost surely, 22114241110403 is an apocalyptic number.
2114241110403 is a deficient number, since it is larger than the sum of its proper divisors (713753389965).
2114241110403 is a wasteful number, since it uses less digits than its factorization.
2114241110403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2251588293.
The product of its (nonzero) digits is 768, while the sum is 24.
Adding to 2114241110403 its reverse (3040111424112), we get a palindrome (5154352534515).
The spelling of 2114241110403 in words is "two trillion, one hundred fourteen billion, two hundred forty-one million, one hundred ten thousand, four hundred three".
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