Base | Representation |
---|---|
bin | 1001100111010100110011… |
… | …11010010001010001110011 |
3 | 2202212012020222201111000111 |
4 | 10303222121322101101303 |
5 | 10232344124233020313 |
6 | 112544404543202151 |
7 | 4311326442124246 |
oct | 463523172212163 |
9 | 82765228644014 |
10 | 21142411220083 |
11 | 681149aa5243a |
12 | 245565a8a6357 |
13 | ba494a8581ba |
14 | 53142623325d |
15 | 269e68d5e43d |
hex | 133a99e91473 |
21142411220083 has 2 divisors, whose sum is σ = 21142411220084. Its totient is φ = 21142411220082.
The previous prime is 21142411220033. The next prime is 21142411220209. The reversal of 21142411220083 is 38002211424112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21142411220083 - 221 = 21142409122931 is a prime.
It is not a weakly prime, because it can be changed into another prime (21142411220033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10571205610041 + 10571205610042.
It is an arithmetic number, because the mean of its divisors is an integer number (10571205610042).
Almost surely, 221142411220083 is an apocalyptic number.
21142411220083 is a deficient number, since it is larger than the sum of its proper divisors (1).
21142411220083 is an equidigital number, since it uses as much as digits as its factorization.
21142411220083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6144, while the sum is 31.
Adding to 21142411220083 its reverse (38002211424112), we get a palindrome (59144622644195).
The spelling of 21142411220083 in words is "twenty-one trillion, one hundred forty-two billion, four hundred eleven million, two hundred twenty thousand, eighty-three".
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