Search a number
-
+
211424131 is a prime number
BaseRepresentation
bin11001001101000…
…01001110000011
3112201211110101101
430212201032003
5413111033011
632551315231
75145034612
oct1446411603
9481743341
10211424131
11a9386096
125a97bb17
1334a57149
1420117879
15138642c1
hexc9a1383

211424131 has 2 divisors, whose sum is σ = 211424132. Its totient is φ = 211424130.

The previous prime is 211424117. The next prime is 211424137. The reversal of 211424131 is 131424112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 211424131 - 215 = 211391363 is a prime.

It is a super-2 number, since 2×2114241312 = 89400326338210322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 211424099 and 211424108.

It is not a weakly prime, because it can be changed into another prime (211424137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105712065 + 105712066.

It is an arithmetic number, because the mean of its divisors is an integer number (105712066).

Almost surely, 2211424131 is an apocalyptic number.

211424131 is a deficient number, since it is larger than the sum of its proper divisors (1).

211424131 is an equidigital number, since it uses as much as digits as its factorization.

211424131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 192, while the sum is 19.

The square root of 211424131 is about 14540.4309083328. The cubic root of 211424131 is about 595.7328079919.

Subtracting from 211424131 its sum of digits (19), we obtain a palindrome (211424112).

Adding to 211424131 its reverse (131424112), we get a palindrome (342848243).

The spelling of 211424131 in words is "two hundred eleven million, four hundred twenty-four thousand, one hundred thirty-one".