Base | Representation |
---|---|
bin | 1100010011101001010… |
… | …1111101000011100101 |
3 | 202012202002001012101121 |
4 | 3010322111331003211 |
5 | 11431003122344031 |
6 | 241044114253541 |
7 | 21163326211645 |
oct | 3047225750345 |
9 | 665662035347 |
10 | 211432231141 |
11 | 81738a8970a |
12 | 34b882872b1 |
13 | 16c269617a1 |
14 | a33a546525 |
15 | 5776e42011 |
hex | 313a57d0e5 |
211432231141 has 4 divisors (see below), whose sum is σ = 211716797472. Its totient is φ = 211147664812.
The previous prime is 211432231117. The next prime is 211432231151. The reversal of 211432231141 is 141132234112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 211432231141 - 221 = 211430133989 is a prime.
It is a super-2 number, since 2×2114322311412 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211432231151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142282051 + ... + 142283536.
It is an arithmetic number, because the mean of its divisors is an integer number (52929199368).
Almost surely, 2211432231141 is an apocalyptic number.
It is an amenable number.
211432231141 is a deficient number, since it is larger than the sum of its proper divisors (284566331).
211432231141 is an equidigital number, since it uses as much as digits as its factorization.
211432231141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 284566330.
The product of its digits is 1152, while the sum is 25.
Adding to 211432231141 its reverse (141132234112), we get a palindrome (352564465253).
The spelling of 211432231141 in words is "two hundred eleven billion, four hundred thirty-two million, two hundred thirty-one thousand, one hundred forty-one".
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