211443363344113 has 2 divisors, whose sum is σ = 211443363344114. Its totient is φ = 211443363344112.

The previous prime is 211443363344063. The next prime is 211443363344131. The reversal of 211443363344113 is 311443363344112.

Together with next prime (211443363344131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 152204357174769 + 59239006169344 = 12337113^2 + 7696688^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211443363344113 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 211443363344113.

It is not a weakly prime, because it can be changed into another prime (211443363341113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105721681672056 + 105721681672057.

It is an arithmetic number, because the mean of its divisors is an integer number (105721681672057).

Almost surely, 2^{211443363344113} is an apocalyptic number.

It is an amenable number.

211443363344113 is a deficient number, since it is larger than the sum of its proper divisors (1).

211443363344113 is an equidigital number, since it uses as much as digits as its factorization.

211443363344113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 746496, while the sum is 43.

Subtracting 211443363344113 from its reverse (311443363344112), we obtain a palindrome (99999999999999).

The spelling of 211443363344113 in words is "two hundred eleven trillion, four hundred forty-three billion, three hundred sixty-three million, three hundred forty-four thousand, one hundred thirteen".