Base | Representation |
---|---|
bin | 1100010011101100000… |
… | …0100110110010011001 |
3 | 202012202212002020210222 |
4 | 3010323000212302121 |
5 | 11431014003141441 |
6 | 241045154045425 |
7 | 21163523230364 |
oct | 3047300466231 |
9 | 665685066728 |
10 | 211443412121 |
11 | 81744326097 |
12 | 34b8bb79875 |
13 | 16c29077a56 |
14 | a33bc170db |
15 | 5777deed4b |
hex | 313b026c99 |
211443412121 has 2 divisors, whose sum is σ = 211443412122. Its totient is φ = 211443412120.
The previous prime is 211443412097. The next prime is 211443412171. The reversal of 211443412121 is 121214344112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 193546323721 + 17897088400 = 439939^2 + 133780^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211443412121 is a prime.
It is not a weakly prime, because it can be changed into another prime (211443412171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105721706060 + 105721706061.
It is an arithmetic number, because the mean of its divisors is an integer number (105721706061).
Almost surely, 2211443412121 is an apocalyptic number.
It is an amenable number.
211443412121 is a deficient number, since it is larger than the sum of its proper divisors (1).
211443412121 is an equidigital number, since it uses as much as digits as its factorization.
211443412121 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1536, while the sum is 26.
Adding to 211443412121 its reverse (121214344112), we get a palindrome (332657756233).
The spelling of 211443412121 in words is "two hundred eleven billion, four hundred forty-three million, four hundred twelve thousand, one hundred twenty-one".
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