Base | Representation |
---|---|
bin | 110000000101000100000111… |
… | …110001101010100100111011 |
3 | 1000201200211101121212010222021 |
4 | 300011010013301222210323 |
5 | 210203431303332001211 |
6 | 2025420424401335311 |
7 | 62353031366311345 |
oct | 6005040761524473 |
9 | 1021624347763867 |
10 | 211454255343931 |
11 | 614152785a4576 |
12 | 1b871302337537 |
13 | 90cb087576572 |
14 | 3a30624cb0295 |
15 | 196a625399771 |
hex | c05107c6a93b |
211454255343931 has 2 divisors, whose sum is σ = 211454255343932. Its totient is φ = 211454255343930.
The previous prime is 211454255343917. The next prime is 211454255344027. The reversal of 211454255343931 is 139343552454112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211454255343931 - 217 = 211454255212859 is a prime.
It is a super-2 number, since 2×2114542553439312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211454255743931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105727127671965 + 105727127671966.
It is an arithmetic number, because the mean of its divisors is an integer number (105727127671966).
Almost surely, 2211454255343931 is an apocalyptic number.
211454255343931 is a deficient number, since it is larger than the sum of its proper divisors (1).
211454255343931 is an equidigital number, since it uses as much as digits as its factorization.
211454255343931 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 7776000, while the sum is 52.
The spelling of 211454255343931 in words is "two hundred eleven trillion, four hundred fifty-four billion, two hundred fifty-five million, three hundred forty-three thousand, nine hundred thirty-one".
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