Base | Representation |
---|---|
bin | 11110110001010100100… |
… | …110010101001101010001 |
3 | 21111011000011011112121122 |
4 | 132301110212111031101 |
5 | 234121041032302423 |
6 | 4255224024132025 |
7 | 305525232005126 |
oct | 36612446251521 |
9 | 7434004145548 |
10 | 2114543244113 |
11 | 7458555984a3 |
12 | 2a1990307015 |
13 | 1245290990b1 |
14 | 744b71d874d |
15 | 3a00dda68c8 |
hex | 1ec54995351 |
2114543244113 has 2 divisors, whose sum is σ = 2114543244114. Its totient is φ = 2114543244112.
The previous prime is 2114543244103. The next prime is 2114543244217. The reversal of 2114543244113 is 3114423454112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2000914924369 + 113628319744 = 1414537^2 + 337088^2 .
It is a cyclic number.
It is not a de Polignac number, because 2114543244113 - 240 = 1015031616337 is a prime.
It is not a weakly prime, because it can be changed into another prime (2114543244103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057271622056 + 1057271622057.
It is an arithmetic number, because the mean of its divisors is an integer number (1057271622057).
Almost surely, 22114543244113 is an apocalyptic number.
It is an amenable number.
2114543244113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2114543244113 is an equidigital number, since it uses as much as digits as its factorization.
2114543244113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 46080, while the sum is 35.
Adding to 2114543244113 its reverse (3114423454112), we get a palindrome (5228966698225).
The spelling of 2114543244113 in words is "two trillion, one hundred fourteen billion, five hundred forty-three million, two hundred forty-four thousand, one hundred thirteen".
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