Base | Representation |
---|---|
bin | 1100010011111100111… |
… | …0011000011000101101 |
3 | 202012221210011012021020 |
4 | 3010333032120120231 |
5 | 11431140104211023 |
6 | 241100201524353 |
7 | 21165342313002 |
oct | 3047716303055 |
9 | 665853135236 |
10 | 211514132013 |
11 | 81780238a88 |
12 | 34bab7a36b9 |
13 | 16c3a909142 |
14 | a3473858a9 |
15 | 577e21dde3 |
hex | 313f39862d |
211514132013 has 4 divisors (see below), whose sum is σ = 282018842688. Its totient is φ = 141009421340.
The previous prime is 211514131993. The next prime is 211514132057. The reversal of 211514132013 is 310231415112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 211514132013 - 218 = 211513869869 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211514131013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35252355333 + ... + 35252355338.
It is an arithmetic number, because the mean of its divisors is an integer number (70504710672).
Almost surely, 2211514132013 is an apocalyptic number.
It is an amenable number.
211514132013 is a deficient number, since it is larger than the sum of its proper divisors (70504710675).
211514132013 is an equidigital number, since it uses as much as digits as its factorization.
211514132013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70504710674.
The product of its (nonzero) digits is 720, while the sum is 24.
Adding to 211514132013 its reverse (310231415112), we get a palindrome (521745547125).
The spelling of 211514132013 in words is "two hundred eleven billion, five hundred fourteen million, one hundred thirty-two thousand, thirteen".
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