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2115311434 = 21057655717
BaseRepresentation
bin111111000010101…
…0001011101001010
312110102022221202221
41332011101131022
513313004431214
6545522244254
7103263564505
oct17605213512
95412287687
102115311434
11996046875
124b04b668a
1327931c192
14160d1413c
15c5a8de24
hex7e15174a

2115311434 has 4 divisors (see below), whose sum is σ = 3172967154. Its totient is φ = 1057655716.

The previous prime is 2115311413. The next prime is 2115311441. The reversal of 2115311434 is 4341135112.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1305738225 + 809573209 = 36135^2 + 28453^2 .

It is a super-2 number, since 2×21153114342 = 8949084925622272712, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2115311399 and 2115311408.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 528827857 + ... + 528827860.

Almost surely, 22115311434 is an apocalyptic number.

2115311434 is a deficient number, since it is larger than the sum of its proper divisors (1057655720).

2115311434 is a wasteful number, since it uses less digits than its factorization.

2115311434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1057655719.

The product of its digits is 1440, while the sum is 25.

The square root of 2115311434 is about 45992.5149779831. The cubic root of 2115311434 is about 1283.6839335039.

Adding to 2115311434 its reverse (4341135112), we get a palindrome (6456446546).

The spelling of 2115311434 in words is "two billion, one hundred fifteen million, three hundred eleven thousand, four hundred thirty-four".

Divisors: 1 2 1057655717 2115311434