Base | Representation |
---|---|
bin | 1100010100000001001… |
… | …1000010101110101001 |
3 | 202020000001000122120022 |
4 | 3011000103002232221 |
5 | 11431204211144431 |
6 | 241102043410225 |
7 | 21165651306614 |
oct | 3050023025651 |
9 | 666001018508 |
10 | 211532131241 |
11 | 8178a412082 |
12 | 34bb5823975 |
13 | 16c4156b982 |
14 | a34990d17b |
15 | 5780ac707b |
hex | 31404c2ba9 |
211532131241 has 2 divisors, whose sum is σ = 211532131242. Its totient is φ = 211532131240.
The previous prime is 211532131229. The next prime is 211532131249. The reversal of 211532131241 is 142131235112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 191734515625 + 19797615616 = 437875^2 + 140704^2 .
It is a cyclic number.
It is not a de Polignac number, because 211532131241 - 230 = 210458389417 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 211532131241.
It is not a weakly prime, because it can be changed into another prime (211532131249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105766065620 + 105766065621.
It is an arithmetic number, because the mean of its divisors is an integer number (105766065621).
Almost surely, 2211532131241 is an apocalyptic number.
It is an amenable number.
211532131241 is a deficient number, since it is larger than the sum of its proper divisors (1).
211532131241 is an equidigital number, since it uses as much as digits as its factorization.
211532131241 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1440, while the sum is 26.
Adding to 211532131241 its reverse (142131235112), we get a palindrome (353663366353).
The spelling of 211532131241 in words is "two hundred eleven billion, five hundred thirty-two million, one hundred thirty-one thousand, two hundred forty-one".
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