Base | Representation |
---|---|
bin | 110000000110011101010011… |
… | …011000101000100101111001 |
3 | 1000202000222120011000202021022 |
4 | 300012131103120220211321 |
5 | 210212013411330144004 |
6 | 2025532422343152225 |
7 | 62362661352133451 |
oct | 6006352330504571 |
9 | 1022028504022238 |
10 | 211550013131129 |
11 | 61451947351382 |
12 | 1b887987445675 |
13 | 910710821a4ca |
14 | 3a3510a76ad61 |
15 | 196cd7be672be |
hex | c06753628979 |
211550013131129 has 2 divisors, whose sum is σ = 211550013131130. Its totient is φ = 211550013131128.
The previous prime is 211550013131063. The next prime is 211550013131141. The reversal of 211550013131129 is 921131310055112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 191016862183225 + 20533150947904 = 13820885^2 + 4531352^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211550013131129 is a prime.
It is not a weakly prime, because it can be changed into another prime (211550013131329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105775006565564 + 105775006565565.
It is an arithmetic number, because the mean of its divisors is an integer number (105775006565565).
Almost surely, 2211550013131129 is an apocalyptic number.
It is an amenable number.
211550013131129 is a deficient number, since it is larger than the sum of its proper divisors (1).
211550013131129 is an equidigital number, since it uses as much as digits as its factorization.
211550013131129 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8100, while the sum is 35.
The spelling of 211550013131129 in words is "two hundred eleven trillion, five hundred fifty billion, thirteen million, one hundred thirty-one thousand, one hundred twenty-nine".
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