Base | Representation |
---|---|
bin | 11110110011000101110… |
… | …101111001011011100111 |
3 | 21111022220120011202121101 |
4 | 132303011311321123213 |
5 | 234133433421300210 |
6 | 4300140333500531 |
7 | 305623301643403 |
oct | 36630565713347 |
9 | 7438816152541 |
10 | 2116443150055 |
11 | 74663aa899a3 |
12 | 2a2220641747 |
13 | 12476c898bb0 |
14 | 7461767a103 |
15 | 3a0c0a96a3a |
hex | 1ecc5d796e7 |
2116443150055 has 24 divisors (see below), whose sum is σ = 2739364864992. Its totient is φ = 1560476173632.
The previous prime is 2116443150053. The next prime is 2116443150089. The reversal of 2116443150055 is 5500513446112.
It is not a de Polignac number, because 2116443150055 - 21 = 2116443150053 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2116443149996 and 2116443150023.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2116443150053) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 27170694 + ... + 27248476.
It is an arithmetic number, because the mean of its divisors is an integer number (114140202708).
Almost surely, 22116443150055 is an apocalyptic number.
2116443150055 is a deficient number, since it is larger than the sum of its proper divisors (622921714937).
2116443150055 is an frugal number, since it uses more digits than its factorization.
2116443150055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 79095 (or 78448 counting only the distinct ones).
The product of its (nonzero) digits is 72000, while the sum is 37.
Adding to 2116443150055 its reverse (5500513446112), we get a palindrome (7616956596167).
The spelling of 2116443150055 in words is "two trillion, one hundred sixteen billion, four hundred forty-three million, one hundred fifty thousand, fifty-five".
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