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211920899126113 is a prime number
BaseRepresentation
bin110000001011110110101101…
…111010011011001101100001
31000210100102212211110102112001
4300023312231322123031201
5210234103000134013423
62030415041141204001
762431531303104412
oct6013665572331541
91023312784412461
10211920899126113
116158516a876901
121b927834400601
139133093bc5638
143a49052037809
1519778378e8cad
hexc0bdade9b361

211920899126113 has 2 divisors, whose sum is σ = 211920899126114. Its totient is φ = 211920899126112.

The previous prime is 211920899126051. The next prime is 211920899126201. The reversal of 211920899126113 is 311621998029112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 183483604454544 + 28437294671569 = 13545612^2 + 5332663^2 .

It is a cyclic number.

It is not a de Polignac number, because 211920899126113 - 217 = 211920898995041 is a prime.

It is not a weakly prime, because it can be changed into another prime (211920899126813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105960449563056 + 105960449563057.

It is an arithmetic number, because the mean of its divisors is an integer number (105960449563057).

Almost surely, 2211920899126113 is an apocalyptic number.

It is an amenable number.

211920899126113 is a deficient number, since it is larger than the sum of its proper divisors (1).

211920899126113 is an equidigital number, since it uses as much as digits as its factorization.

211920899126113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 839808, while the sum is 55.

The spelling of 211920899126113 in words is "two hundred eleven trillion, nine hundred twenty billion, eight hundred ninety-nine million, one hundred twenty-six thousand, one hundred thirteen".