Base | Representation |
---|---|
bin | 110000001101000001011011… |
… | …011101001111000011011011 |
3 | 1000210122002221120102012120201 |
4 | 300031001123131033003123 |
5 | 210241411243222333201 |
6 | 2030515545311403031 |
7 | 62440401250235212 |
oct | 6015013335170333 |
9 | 1023562846365521 |
10 | 212001120121051 |
11 | 616061964a5728 |
12 | 1b93b2a2223477 |
13 | 913a809a55991 |
14 | 3a4cca229c079 |
15 | 19799804bc801 |
hex | c0d05b74f0db |
212001120121051 has 2 divisors, whose sum is σ = 212001120121052. Its totient is φ = 212001120121050.
The previous prime is 212001120120989. The next prime is 212001120121057. The reversal of 212001120121051 is 150121021100212.
212001120121051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 212001120121051 - 217 = 212001119989979 is a prime.
It is not a weakly prime, because it can be changed into another prime (212001120121057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106000560060525 + 106000560060526.
It is an arithmetic number, because the mean of its divisors is an integer number (106000560060526).
Almost surely, 2212001120121051 is an apocalyptic number.
212001120121051 is a deficient number, since it is larger than the sum of its proper divisors (1).
212001120121051 is an equidigital number, since it uses as much as digits as its factorization.
212001120121051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 19.
Adding to 212001120121051 its reverse (150121021100212), we get a palindrome (362122141221263).
The spelling of 212001120121051 in words is "two hundred twelve trillion, one billion, one hundred twenty million, one hundred twenty-one thousand, fifty-one".
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