Base | Representation |
---|---|
bin | 11110110110100000000… |
… | …011011001011010011111 |
3 | 21111200100200221102000110 |
4 | 132312200003121122133 |
5 | 234213433123401030 |
6 | 4301543513101103 |
7 | 306113104461135 |
oct | 36664003313237 |
9 | 7450320842013 |
10 | 2120104122015 |
11 | 748149562360 |
12 | 2a2a826b7793 |
13 | 124c041a64a9 |
14 | 7488397b755 |
15 | 3a23719e1b0 |
hex | 1eda00d969f |
2120104122015 has 32 divisors (see below), whose sum is σ = 3700708526592. Its totient is φ = 1027883952000.
The previous prime is 2120104122013. The next prime is 2120104122023. The reversal of 2120104122015 is 5102214010212.
It is not a de Polignac number, because 2120104122015 - 21 = 2120104122013 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2120104121982 and 2120104122000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2120104122013) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3634305 + ... + 4177125.
It is an arithmetic number, because the mean of its divisors is an integer number (115647141456).
Almost surely, 22120104122015 is an apocalyptic number.
2120104122015 is a deficient number, since it is larger than the sum of its proper divisors (1580604404577).
2120104122015 is a wasteful number, since it uses less digits than its factorization.
2120104122015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 566511.
The product of its (nonzero) digits is 320, while the sum is 21.
Adding to 2120104122015 its reverse (5102214010212), we get a palindrome (7222318132227).
The spelling of 2120104122015 in words is "two trillion, one hundred twenty billion, one hundred four million, one hundred twenty-two thousand, fifteen".
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