Base | Representation |
---|---|
bin | 110000001101001010101110… |
… | …111110001011011010111011 |
3 | 1000210200001201212101121221012 |
4 | 300031022232332023122323 |
5 | 210242042223431403233 |
6 | 2030524320535104135 |
7 | 62441203656064442 |
oct | 6015125676133273 |
9 | 1023601655347835 |
10 | 212011111200443 |
11 | 6160a453177535 |
12 | 1b94121021204b |
13 | 913b73c93b989 |
14 | 3a4d56d17bd59 |
15 | 1979d676b7548 |
hex | c0d2aef8b6bb |
212011111200443 has 2 divisors, whose sum is σ = 212011111200444. Its totient is φ = 212011111200442.
The previous prime is 212011111200433. The next prime is 212011111200461. The reversal of 212011111200443 is 344002111110212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212011111200443 - 26 = 212011111200379 is a prime.
It is a super-2 number, since 2×2120111112004432 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (212011111200403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106005555600221 + 106005555600222.
It is an arithmetic number, because the mean of its divisors is an integer number (106005555600222).
Almost surely, 2212011111200443 is an apocalyptic number.
212011111200443 is a deficient number, since it is larger than the sum of its proper divisors (1).
212011111200443 is an equidigital number, since it uses as much as digits as its factorization.
212011111200443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 212011111200443 its reverse (344002111110212), we get a palindrome (556013222310655).
The spelling of 212011111200443 in words is "two hundred twelve trillion, eleven billion, one hundred eleven million, two hundred thousand, four hundred forty-three".
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