21201200000113 has 32 divisors (see below), whose sum is σ = 25032342601728. Its totient is φ = 17571638145600.

The previous prime is 21201200000089. The next prime is 21201200000129. The reversal of 21201200000113 is 31100000210212.

It is not a de Polignac number, because 21201200000113 - 2³³ = 21192610065521 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21201200000093 and 21201200000102.

It is not an unprimeable number, because it can be changed into a prime (21201200000713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1912252056 + ... + 1912263142.

It is an arithmetic number, because the mean of its divisors is an integer number (782260706304).

Almost surely, 2^{21201200000113} is an apocalyptic number.

It is an amenable number.

21201200000113 is a deficient number, since it is larger than the sum of its proper divisors (3831142601615).

21201200000113 is a wasteful number, since it uses less digits than its factorization.

21201200000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17653.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 21201200000113 its reverse (31100000210212), we get a palindrome (52301200210325).

The spelling of 21201200000113 in words is "twenty-one trillion, two hundred one billion, two hundred million, one hundred thirteen", and thus it is an aban number.