Base | Representation |
---|---|
bin | 11110110110100001000… |
… | …100111011010100111001 |
3 | 21111200101220021011011112 |
4 | 132312201010323110321 |
5 | 234214002023102111 |
6 | 4301545325210105 |
7 | 306113403465425 |
oct | 36664104732471 |
9 | 7450356234145 |
10 | 2120121300281 |
11 | 748158225676 |
12 | 2a2a88400935 |
13 | 124c0790c44a |
14 | 74885d6db85 |
15 | 3a238943e8b |
hex | 1eda113b539 |
2120121300281 has 2 divisors, whose sum is σ = 2120121300282. Its totient is φ = 2120121300280.
The previous prime is 2120121300257. The next prime is 2120121300391. The reversal of 2120121300281 is 1820031210212.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1630688136256 + 489433164025 = 1276984^2 + 699595^2 .
It is a cyclic number.
It is not a de Polignac number, because 2120121300281 - 26 = 2120121300217 is a prime.
It is a super-2 number, since 2×21201213002812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2120121300181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060060650140 + 1060060650141.
It is an arithmetic number, because the mean of its divisors is an integer number (1060060650141).
Almost surely, 22120121300281 is an apocalyptic number.
It is an amenable number.
2120121300281 is a deficient number, since it is larger than the sum of its proper divisors (1).
2120121300281 is an equidigital number, since it uses as much as digits as its factorization.
2120121300281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 2120121300281 its reverse (1820031210212), we get a palindrome (3940152510493).
The spelling of 2120121300281 in words is "two trillion, one hundred twenty billion, one hundred twenty-one million, three hundred thousand, two hundred eighty-one".
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