Base | Representation |
---|---|
bin | 1100010101110011110… |
… | …1110111111101010001 |
3 | 202021020120002110222012 |
4 | 3011130331313331101 |
5 | 11433200324340421 |
6 | 241221504552305 |
7 | 21213611540306 |
oct | 3053475677521 |
9 | 667216073865 |
10 | 212013121361 |
11 | 81a06975078 |
12 | 3510a922695 |
13 | 16cba0c9202 |
14 | a3937570ad |
15 | 57ace3795b |
hex | 315cf77f51 |
212013121361 has 2 divisors, whose sum is σ = 212013121362. Its totient is φ = 212013121360.
The previous prime is 212013121319. The next prime is 212013121373. The reversal of 212013121361 is 163121310212.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 188925838336 + 23087283025 = 434656^2 + 151945^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-212013121361 is a prime.
It is a super-2 number, since 2×2120131213612 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (212013121301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106006560680 + 106006560681.
It is an arithmetic number, because the mean of its divisors is an integer number (106006560681).
Almost surely, 2212013121361 is an apocalyptic number.
It is an amenable number.
212013121361 is a deficient number, since it is larger than the sum of its proper divisors (1).
212013121361 is an equidigital number, since it uses as much as digits as its factorization.
212013121361 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 212013121361 its reverse (163121310212), we get a palindrome (375134431573).
The spelling of 212013121361 in words is "two hundred twelve billion, thirteen million, one hundred twenty-one thousand, three hundred sixty-one".
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